Class 11 Computer Science Chapter 03 · 23 min read

Boolean Logic

Unit 1 · Ch 3 Oct 05, 2026
Chapter Quiz Share

Every decision a computer makes — every "if this, then that" — comes down to two values: TRUE or FALSE. Boolean Logic is the algebra of these two values. This chapter covers truth tables, the basic and derived logic gates, the postulates and theorems of Boolean algebra, DeMorgan's Theorems, and how to draw logic circuits for Boolean expressions.

💡 How to use these notes

Build a truth table for every law and gate yourself instead of only memorising it. Pay particular attention to DeMorgan's Theorems, Basic Logic Gates and Boolean Law simplification during revision.


3.1 📜 Development of Boolean Logic

Boolean Logic (also called Boolean Algebra) was developed by the mathematician George Boole in the 1850s — a system of logic using only TWO values: TRUE (1) and FALSE (0).

graph LR
    BOOLE["👨‍🔬 George Boole\n(1854)\n'An Investigation of\nthe Laws of Thought'"]
    ALGEBRA["🧮 Boolean Algebra\n(Mathematical logic\nsystem)"]
    COMPUTERS["💻 Modern Computers\n(Built on TRUE/FALSE\ncircuit logic!)"]

    BOOLE --> ALGEBRA --> COMPUTERS

    style BOOLE fill:#9C27B0,color:#fff
    style COMPUTERS fill:#4CAF50,color:#fff

Why does this matter for computers? Remember from Chapter 1 — computers are just millions of switches, each either ON or OFF. Boolean Logic gives us the MATHEMATICAL RULES to combine and simplify these ON/OFF (TRUE/FALSE) values — this is literally how ALL digital circuits and computer decision-making work!

Fact Detail
Developed by George Boole
Published in 1854, in his book "An Investigation of the Laws of Thought"
Core Idea Logic can be expressed using only two values and mathematical operations
Modern Use Foundation of digital circuits, programming conditions, database queries

3.2 🔢 Binary Valued Quantities

A Binary Valued Quantity is any variable that can hold ONLY ONE of TWO possible values.

graph LR
    T["✅ TRUE\n1\nHIGH\nYES\nON"]
    F["❌ FALSE\n0\nLOW\nNO\nOFF"]

    style T fill:#4CAF50,color:#fff
    style F fill:#F44336,color:#fff
✅

TRUE / 1

Represents an affirmative, ON, or HIGH state

Light switch ONcondition satisfied
❌

FALSE / 0

Represents a negative, OFF, or LOW state

Light switch OFFcondition not satisfied

Real-World Examples of Binary Values:

Real-World Example TRUE (1) FALSE (0)
Light Switch ON OFF
Door Open Closed
Exam Result Pass Fail
Login Status Logged In Logged Out
📋 Board Exam Tip

"What is a Binary Valued Quantity?" — 1-mark question! Answer: A variable that can take only ONE of TWO possible values — typically represented as TRUE/FALSE or 1/0.


3.3 🔧 Logical Operations

3.3.1 Logical Function or Compound Statement 📝

A Logical Function (or Compound Statement) is an expression formed by combining ONE OR MORE Boolean variables using logical operators, producing a TRUE or FALSE result.

Example: Y = A AND B
Here, Y is the logical function, A and B are Boolean variables,
and AND is the logical operator combining them.

Analogy: Think of a logical function like a RECIPE. The ingredients (A, B) go IN, an operation (AND/OR/NOT) is applied, and a single RESULT (TRUE or FALSE) comes OUT!


3.3.2 Logical Operators 🔧

The THREE fundamental logical operators form the foundation of ALL Boolean logic:

graph TD
    OPS["🔧 LOGICAL OPERATORS"]
    NOT["🚫 NOT\n(Inverts the value)"]
    AND["✖️ AND\n(TRUE only if BOTH true)"]
    OR["➕ OR\n(TRUE if AT LEAST ONE true)"]

    OPS --> NOT
    OPS --> AND
    OPS --> OR

    style NOT fill:#F44336,color:#fff
    style AND fill:#2196F3,color:#fff
    style OR fill:#4CAF50,color:#fff
🚫

NOT (¬ or ')

Reverses/inverts a single value

NOT TRUE = FALSE
✖️

AND (·)

TRUE only when BOTH inputs are TRUE

"I'll go out AND it's sunny" — both conditions must hold
➕

OR (+)

TRUE when AT LEAST ONE input is TRUE

"I'll eat pizza OR pasta" — either one satisfies it

Symbols Used in Boolean Expressions:

Operator Common Symbols
AND · or ∧ or simply juxtaposition (AB)
OR + or ∨
NOT ¬ or ' (apostrophe) or a bar over the variable (Ā)
📋 Board Exam Tip

"Name the three basic logical operators." — 1-mark question! Answer: AND, OR, NOT


3.3.3 Evaluation of Boolean Expressions using Truth Table 📊

A Truth Table lists ALL possible combinations of input values and the corresponding output result — the ultimate "cheat sheet" for any Boolean expression!

Truth Table for AND:

A B A AND B
0 0 0
0 1 0
1 0 0
1 1 1

Truth Table for OR:

A B A OR B
0 0 0
0 1 1
1 0 1
1 1 1

Truth Table for NOT:

A NOT A
0 1
1 0

Memory Trick! 🎵 AND = Strict Boss — needs EVERYONE to say yes. OR = Easy-going friend — just needs ONE yes. NOT = The Opposite Person — always disagrees!

Evaluating a Compound Expression: Y = A·B + C

A B C A·B Y = A·B + C
0 0 0 0 0
0 0 1 0 1
0 1 0 0 0
0 1 1 0 1
1 0 0 0 0
1 0 1 0 1
1 1 0 1 1
1 1 1 1 1
📋 Board Exam Tip

"Draw the truth table for Y = A + B'." — 2-mark question. Answer: Evaluate B' (NOT B) first for each row, then apply OR with A. Total rows = 2ⁿ where n = number of variables (here, 2² = 4 rows).


3.4 🚪 Basic Logic Gates

A Logic Gate is a physical electronic circuit that implements a Boolean/logical operation — taking one or more inputs and producing ONE output.

3.4.1 Inverter (NOT Gate) 🚫

graph LR
    IN["A"] -->|"NOT Gate\n—▷o—"| OUT["Ā (NOT A)"]

    style IN fill:#2196F3,color:#fff
    style OUT fill:#F44336,color:#fff

Truth Table:

A Output (Ā)
0 1
1 0

The NOT gate has only ONE input and simply FLIPS/inverts it.


3.4.2 OR Gate ➕

graph LR
    A["A"] --> GATE["OR Gate"]
    B["B"] --> GATE
    GATE --> OUT["A + B"]

    style GATE fill:#4CAF50,color:#fff

Truth Table:

A B A + B
0 0 0
0 1 1
1 0 1
1 1 1

OR Gate Rule: Output is TRUE if AT LEAST ONE input is TRUE. Only FALSE when BOTH inputs are FALSE.


3.4.3 AND Gate ✖️

graph LR
    A["A"] --> GATE["AND Gate"]
    B["B"] --> GATE
    GATE --> OUT["A · B"]

    style GATE fill:#2196F3,color:#fff

Truth Table:

A B A · B
0 0 0
0 1 0
1 0 0
1 1 1

AND Gate Rule: Output is TRUE ONLY when BOTH inputs are TRUE. Any single FALSE input makes the whole output FALSE.

📋 Board Exam Tip

"Draw the logic symbol and truth table for AND, OR, and NOT gates." — 3-mark question.


3.5 📐 Basic Postulates of Boolean Logic

Postulates are the fundamental, self-evident RULES that form the foundation of Boolean Algebra — accepted as true without needing proof.

1️⃣

Closure

Combining two Boolean values with AND/OR always gives another Boolean value

1 AND 0 = 0 (still a valid Boolean value)
2️⃣

Identity Elements

0 is the identity for OR; 1 is the identity for AND

A + 0 = AA · 1 = A
3️⃣

Commutativity

Order doesn't matter for AND/OR

A+B = B+A
4️⃣

Distributivity

AND distributes over OR and vice versa

A·(B+C) = A·B + A·C
5️⃣

Complement

Every value A has a complement A' such that A+A'=1 and A·A'=0

Fundamental for NOT operation

3.6 🔄 Principle of Duality

The Principle of Duality states that EVERY valid Boolean expression remains valid if you SWAP:

  • AND ↔ OR
  • 0 ↔ 1
graph LR
    ORIG["Original Expression\nA + 0 = A"]
    SWAP["Swap AND↔OR, 0↔1"]
    DUAL["Dual Expression\nA · 1 = A"]

    ORIG --> SWAP --> DUAL

    style ORIG fill:#2196F3,color:#fff
    style DUAL fill:#4CAF50,color:#fff

More Duality Examples:

Original Dual (swap AND↔OR, 0↔1)
A + 1 = 1 A · 0 = 0
A + A = A A · A = A
A + A' = 1 A · A' = 0

Analogy: Duality is like a MIRROR IMAGE — every rule has a "twin" rule where AND and OR simply swap places, and 0/1 swap places too. If one is TRUE, the mirrored version is AUTOMATICALLY true as well!

📋 Board Exam Tip

"Write the dual of the expression: A·(B+C)" — 1-mark question! Answer: Swap · with +, and + with ·: A + (B·C)


3.7 📜 Basic Theorems of Boolean Algebra/Logic

These are the LAWS you'll use CONSTANTLY to simplify Boolean expressions — memorise them well!

3.7.1 Properties of 0 and 1

Law Expression
OR with 0 A + 0 = A
OR with 1 A + 1 = 1
AND with 0 A · 0 = 0
AND with 1 A · 1 = A

3.7.2 Indempotence Law

"Combining a variable with ITSELF changes nothing."

Law Expression
OR form A + A = A
AND form A · A = A

3.7.3 Involution (Double Negation)

"NOT-NOT A equals A" — flipping twice returns the original!

(A')' = A

Analogy: Like saying "It's NOT that I DON'T like pizza" — the double negative means you DO like pizza! Two NOTs cancel out.


3.7.4 Complementarity Law

Law Expression
OR form A + A' = 1
AND form A · A' = 0

A value combined with its OPPOSITE via OR is ALWAYS true; combined via AND is ALWAYS false.


3.7.5 Commutative Law

"Order doesn't matter" — just like in regular math!

Law Expression
OR form A + B = B + A
AND form A · B = B · A

3.7.6 Associative Law

"Grouping doesn't matter" — how you bracket the terms doesn't change the result.

Law Expression
OR form (A+B)+C = A+(B+C)
AND form (A·B)·C = A·(B·C)

3.7.7 Distributive Law

"AND/OR distribute over each other" — similar to multiplication distributing over addition in regular math.

Law Expression
AND over OR A·(B+C) = A·B + A·C
OR over AND A+(B·C) = (A+B)·(A+C)
🧠 The SECOND Distributive Law is UNIQUE to Boolean Algebra! 🧠

In regular math, addition does NOT distribute over multiplication (2+(3×4) ≠ (2+3)×(2+4)). But in Boolean Algebra, BOTH directions work! This is a key difference students often miss.


3.7.8 Absorption Law

"A larger expression gets 'absorbed' into a simpler one."

Law Expression
Form 1 A + (A·B) = A
Form 2 A · (A+B) = A

Analogy: If you already own a "car" (A), owning "a car AND a specific model of that car" (A·B) doesn't add anything NEW — it's absorbed into just owning "a car" (A)!


3.7.9 Some Other Rules of Boolean Logic Algebra

Rule Expression
Redundancy Law A + A'B = A + B
Consensus Theorem AB + A'C + BC = AB + A'C

Complete Boolean Laws — Master Summary Table:

Law Name OR Form AND Form
Identity A+0=A A·1=A
Null/Dominant A+1=1 A·0=0
Idempotent A+A=A A·A=A
Complement A+A'=1 A·A'=0
Commutative A+B=B+A A·B=B·A
Associative (A+B)+C=A+(B+C) (A·B)·C=A·(B·C)
Distributive A+(B·C)=(A+B)·(A+C) A·(B+C)=A·B+A·C
Absorption A+(A·B)=A A·(A+B)=A
📋 Board Exam Tip

"Simplify the expression: Y = A + A·B" — 2-mark question, uses Absorption Law! Answer: By Absorption Law, A + A·B = A


3.8 🔄 DeMorgan's Theorems

DeMorgan's Theorems are central to this chapter — they explain how NOT interacts with AND/OR!

3.8.1 DeMorgan's First Theorem

(A · B)' = A' + B'

"The complement of an AND expression equals
 the OR of the individual complements"

Verification via Truth Table:

A B A·B (A·B)' A' B' A'+B'
0 0 0 1 1 1 1 ✅
0 1 0 1 1 0 1 ✅
1 0 0 1 0 1 1 ✅
1 1 1 0 0 0 0 ✅

Both (A·B)' and A'+B' produce IDENTICAL results in every row — proving the theorem!


3.8.2 DeMorgan's Second Theorem

(A + B)' = A' · B'

"The complement of an OR expression equals
 the AND of the individual complements"

Verification via Truth Table:

A B A+B (A+B)' A' B' A'·B'
0 0 0 1 1 1 1 ✅
0 1 1 0 1 0 0 ✅
1 0 1 0 0 1 0 ✅
1 1 1 0 0 0 0 ✅

Memory Trick! 🎵 "Break the bar, change the operator!" When you push a NOT bar INSIDE brackets, it BREAKS apart onto each variable, AND the operator FLIPS (AND↔OR)!

graph TD
    A["(A·B)'"]
    B["Break the bar,\nFlip AND to OR"]
    C["A' + B'"]

    A --> B --> C

    style A fill:#F44336,color:#fff
    style C fill:#4CAF50,color:#fff
📋 Board Exam Tip

"State and verify DeMorgan's First Theorem using a truth table." — 3-mark question. Answer: (A·B)' = A'+B'. Verify by constructing truth tables for both sides and showing they match in every row (as shown above).


3.9 🚪 More about Logic Gates

Beyond the basic 3 gates, these DERIVED gates are built by COMBINING basic gates — and are extremely important in circuit design!

graph TD
    MORE["🚪 MORE LOGIC GATES"]
    NOR["NOR = NOT(OR)"]
    NAND["NAND = NOT(AND)"]
    XOR["XOR = Exclusive OR"]
    XNOR["XNOR = Exclusive NOR"]

    MORE --> NOR
    MORE --> NAND
    MORE --> XOR
    MORE --> XNOR

    style NOR fill:#FF9800,color:#fff
    style NAND fill:#9C27B0,color:#fff
    style XOR fill:#F44336,color:#fff
    style XNOR fill:#2196F3,color:#fff

3.9.1 NOR Gate (NOT + OR)

Truth Table:

A B A+B NOR = (A+B)'
0 0 0 1
0 1 1 0
1 0 1 0
1 1 1 0

NOR = OR gate followed by a NOT — output is the exact OPPOSITE of a regular OR gate!


3.9.2 NAND Gate (NOT + AND)

Truth Table:

A B A·B NAND = (A·B)'
0 0 0 1
0 1 0 1
1 0 0 1
1 1 1 0

NAND = AND gate followed by a NOT — output is the exact OPPOSITE of a regular AND gate!

🧠 NAND and NOR are "Universal Gates"! 🧠

Fun fact: EITHER a NAND gate ALONE, or a NOR gate ALONE, can be used to build ANY other logic gate (AND, OR, NOT, everything)! This is why they're called "Universal Gates" — extremely important in real hardware design.


3.9.3 XOR Gate (Exclusive OR)

Truth Table:

A B A ⊕ B
0 0 0
0 1 1
1 0 1
1 1 0

XOR Rule: Output is TRUE only when inputs are DIFFERENT from each other. If BOTH are the same (both 0 or both 1), output is FALSE.

Analogy: XOR is like an "Either-Or, but NOT Both" situation — "You can have cake OR ice cream" (not both, and not neither)!


3.9.4 XNOR Gate (Exclusive NOR)

Truth Table:

A B XNOR = (A⊕B)'
0 0 1
0 1 0
1 0 0
1 1 1

XNOR Rule: Output is TRUE when inputs are the SAME (both 0 or both 1) — exactly the OPPOSITE of XOR!

All 7 Logic Gates — Complete Summary Table:

Gate Symbol Output TRUE When...
AND · BOTH inputs are 1
OR + AT LEAST ONE input is 1
NOT ' Input is 0 (inverts)
NAND (·)' NOT both 1 (opposite of AND)
NOR (+)' NEITHER is 1 (opposite of OR)
XOR ⊕ Inputs are DIFFERENT
XNOR (⊕)' Inputs are the SAME
📋 Board Exam Tip

"Differentiate between XOR and XNOR gate with truth tables." — 2-mark question. Answer: XOR gives TRUE when inputs DIFFER (0,1 or 1,0). XNOR gives TRUE when inputs are the SAME (0,0 or 1,1) — it's the exact complement of XOR.


3.10 🔌 Logic Circuits

A Logic Circuit combines MULTIPLE logic gates together to implement a COMPLEX Boolean expression.

Example: Building the circuit for Y = A·B + C

graph LR
    A["A"] --> AND["AND Gate"]
    B["B"] --> AND
    AND --> OR["OR Gate"]
    C["C"] --> OR
    OR --> Y["Y = A·B + C"]

    style AND fill:#2196F3,color:#fff
    style OR fill:#4CAF50,color:#fff

Steps to Draw a Logic Circuit from a Boolean Expression:

  1. Identify all the input variables
  2. Identify the operators used (AND/OR/NOT) and their ORDER
  3. Draw gates matching each operator, connecting inputs correctly
  4. Follow operator precedence: NOT is applied FIRST, then AND, then OR (just like math's BODMAS!)
📋 Board Exam Tip

"Draw the logic circuit for the Boolean expression Y = (A+B)·C'" — 3-mark question, common practical question! Steps: (1) OR gate for A+B, (2) NOT gate for C', (3) AND gate combining the OR output with C' output.


⚠️ Common Errors and Misconceptions

Mistake What's Wrong Correct Understanding
❌ Confusing AND and OR truth tables Different rules for TRUE output ✅ AND needs BOTH true; OR needs AT LEAST ONE true
❌ Applying DeMorgan's without flipping the operator Only breaking the bar, not swapping AND/OR ✅ Must BOTH break the bar AND swap AND↔OR
❌ Thinking XOR and OR are the same XOR excludes the "both true" case ✅ XOR is FALSE when both inputs are TRUE; OR is TRUE in that case
❌ Forgetting Distributive Law works BOTH ways in Boolean Algebra Assuming it only works like regular math ✅ BOTH A·(B+C)=AB+AC AND A+(BC)=(A+B)(A+C) are valid
❌ Thinking NAND/NOR are just "extra" gates with no special use Underestimating their importance ✅ NAND and NOR are UNIVERSAL gates — can build any other gate from them alone
❌ Applying Absorption Law incorrectly Confusing which terms get absorbed ✅ A+(A·B)=A — the SMALLER standalone term "wins"

🎯 Sample Exam Questions

Q1: Very Short Answer [1 mark each]

a) Who developed Boolean Logic? → George Boole

b) What are the two values used in Boolean Algebra? → TRUE (1) and FALSE (0)

c) Write the dual of A + 0 = A. → A · 1 = A

d) State DeMorgan's First Theorem. → (A·B)' = A' + B'

e) Which gate gives TRUE output only when both inputs differ? → XOR Gate


Q2: Short Answer [2 marks]

Q: Simplify the Boolean expression: Y = A + A'B

Using the Redundancy Law: A + A'B = A + B Answer: Y = A + B


Q3: Short Answer [3 marks]

Q: State and verify DeMorgan's Second Theorem using a truth table.

Statement: (A+B)' = A' · B'

A B A+B (A+B)' A' B' A'·B'
0 0 0 1 1 1 1
0 1 1 0 1 0 0
1 0 1 0 0 1 0
1 1 1 0 0 0 0

Both columns (A+B)' and A'·B' match exactly, verifying the theorem.


Q4: Truth Table [2 marks]

Q: Draw the truth table for Y = AB' + A'B

A B B' A' AB' A'B Y=AB'+A'B
0 0 1 1 0 0 0
0 1 0 1 0 1 1
1 0 1 0 1 0 1
1 1 0 0 0 0 0

(Notice: this is exactly the XOR truth table!)


Q5: Circuit Drawing [3 marks]

Q: Draw the logic circuit for Y = (A + B)·C

Steps: (1) Feed A and B into an OR gate. (2) Take the OR gate's output and C into an AND gate. (3) The AND gate's output is Y.


✏️ Practice Problems

  1. Construct the truth table for the expression Y = (A+B)·(A+C).

  2. Simplify: Y = A·(A+B) using the Absorption Law.

  3. State DeMorgan's First Theorem and apply it to simplify (A'+B')'.

  4. Differentiate between NAND and NOR gates with truth tables.

  5. Write the dual of the expression: A·(B+C) = A·B + A·C

  6. Draw the logic circuit for Y = A'·B + A·B'

  7. Explain why NAND and NOR gates are called "Universal Gates."

  8. Simplify the expression Y = AB + A'C + BC using the Consensus Theorem.

  9. Construct a truth table comparing XOR and XNOR gates for the same two inputs A and B.

  10. A circuit has inputs A, B, C, and the Boolean expression Y = A·B + A·C. Simplify this expression using the Distributive Law and draw the simplified logic circuit.

Take the Chapter 03 Quiz Custom Quiz
Learning Support

Need Help With This Chapter?

Save key topics for exam revision, ask questions to teachers, or submit content corrections.

Verified Doubts & Teacher Answers

Chapter 03 Quiz